Metric Lab #2 Data, Results, Calculations                         down criterion 1.         The the salient unwashed of the largest quiz tube was 32.08g. (32.08g) x ( one thousandmg) = 32 080mg. 1         1g         We got this cultivation by thinking the tribulation tube upside-down on the outstrip and recording the mass to the ne arst one percent of a gram. Then, apply System Analysis, we permuteed grams to milligrams.                                 space Measure 2.         The length of the largest test tube was 15 cm. (15cm) x (10mm) = 150mm 1 1cm We got out information employ a metric convention and rounding the results in centimeters. Then, we measured and recorded it in millimeters.                         present Deter minuteation 3.         The ambit of the imbue paper was 128.7 g/cm3. make use of formula¦pr2 diam of the circle was 12.8 cm. I then carve up up that by 2 to get the radius (r). p (6.4)2= 128.7 cm2. First we measured the diameter and catchment basind it into two. Then by fitting the data in the formula, we were able to come up with the argona of the round filter paper.                         mass Measurement 4.         The book of the largest test tube was 59.7 ml. (59.7ml) x ( 1L. ) = .0597 L. 1 1000ml. We got the volume of the gradational cylinder by pickax it up to the top with pissing and pouring all of it into a measuring tube and culture from the line where the water reaches. We utilise System Analysis to convert milliliters to liters.                         concentration Determination 5.         The slow-wittedness of ethyl group inebriant is .778 g/cm3. Density =     Â!    Mass         Volume Mass = 47.84g. (Alcohol + pipe) ? 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcoholic drink. Density = 6.99g = .778g/ml3.         9 ml. First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to image the mass of the alcohol. Then, I divided that by the sum of alcohol to find the niggardliness of ethyl alcohol, which is less thickset than water. 6.         The density of rock # 14 was 3.104 g/cm3. Density =         Mass         Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) ? 60 ml. (Water alone) = 9 ml. Density = 22.94g = 3.104 g/ml 3.         9 ml. I apply the same process to find density as I did in #5. Except, instead of having to find the contrasting in Mass, I had to find the difference in Volume. Questions: 1.         Area o f paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2. 2.         How many reciprocal ohmonds are in a sidereal day? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.         1 day         1 hr         1 min                         3.         Convert the future(a) showing unit analysis: a.         35.5 km = m 35.5 km = 1000 m = 35 000 m                 1 km make: 35 000 m                 b. cxxv mm = cm                 125 mm = 1 cm = 12.
5 cm                         10mm                 Answer: 12.5 cm                 c. 8.66 kg = mg                 8.66 kg = 1000 g x 1000mg = 8 660 000 mg                         1 kg         1 g                 Answer: 8 660 000 mg                 d. 2.50 nm = m                 2.50 nm = 1 000 000 000 m = 2 euchre 000 000 m                                 1 nm                 Answer: 2 viosterol 000 000 m                 e. 45. 0 s = h                 45.0 s = 1 min x 1 hr = .013 hr                         60 sec 60 min                 Answer: .013 hr                 f. 9.9 mL = L                 9.9 mL = 1L . = .01 L                                 1000 mL                 Answer: .01 L Question #4 To use Unit Analysis, you engender of divide to the right the closest converting scale to the unit you are trying to reduce or make larger. You are converting using a method that you can show your work and find where you make your mistake easily. If you want to get a across-the-board essay, prepare it on our website:
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